Cirrus clouds form more than 6,000 meters above Earth. Write an inequality to represent h, the height, in meters, or cirrus clouds.

QUESTION POSTED AT 10/10/2019 - 09:38 AM

Answered by answersmine AT 10/10/2019 - 09:38 AM

More than: > symbol
6,000 meters: your numerical value
clouds: x represents clouds

x>6,000 
Post your answer

Related questions

70/294 in the simplest form

70/294 should equal 5/21.
(I used a converting calculator.)

Hope this helps! :)

ANSWERED AT 17/10/2019 - 09:14 AM


QUESTION POSTED AT 17/10/2019 - 09:14 AM

What is the simplified form of the cube root of x squared times the third root of x squared

The cubic root of x, by itself, would simply be 1/3 x. but, when you have an exponent in the radicand as an unknown, it gets more complicated. first, you have to solve what is inside the radicand first, following order of operations. so, first you solve x squared. x is your unknown, so you would need to determine the value of x and then square it. after that, you cube your answer. if we place 2 as x, for an example, you would find 2 squared to be 4, then cube that for your answer.

ANSWERED AT 17/10/2019 - 09:13 AM


QUESTION POSTED AT 17/10/2019 - 09:13 AM

If JM = 5x – 8 and LM = 2x – 6, which expression represents JL?

The green line is LM
The red line is JM
The blue point is at the coordinates (2/3, -14/3)


you'll have to excuse the way my graph looks. my graphing application on my computer is weird 

ANSWERED AT 17/10/2019 - 09:11 AM


QUESTION POSTED AT 17/10/2019 - 09:11 AM

How would you write 0x+19y=38 in slope-intercept form?

Basically, we need to isolate y

Assuming 0 is unnecessary:

x + 19y = 38
19y = -x + 38
y= \frac{-x+38}{19}
y= -\frac{x}{19} +  \frac{38}{19}
y= -\frac{x}{19} +2



Assuming that 0 is necessary:

0x+19y = 38

0•x is equivalent to 0 so that cancels out x leaving us with

19y = 38

y = 38/19

y = 2


If the 0 is necessary, your answer is y = 2.
If the 0 is unnecessary, your answer is y = -(x/19)+2

ANSWERED AT 17/10/2019 - 09:08 AM


QUESTION POSTED AT 17/10/2019 - 09:08 AM

Please find the volume of each figure . Please show and explain all work or you will be reported do all and not some . 40) A 5m×3m×4m rectangular prism 41) A cube with edge of 6 ft 42) A cylinder with a height of 14 cm and base Diameter of 10 cm 43) A triangular prism with a base area of 15 square inches and height of 12 inches . 44) A cylinder with a base circumference of 8pi and height 7 45) A box has a volume of 24 ft^3 and base of 2 ft by 3 ft, what is the height ?

Volume formulas:
rectangle prism: l×w×h
cube: s^3
cylinder:(pi)r^2×h
triangle prism: (a×b/2)×h
cylinder:(pi)r^2×h
box:l×w×h

40) 5m×3m×4m =15m×4m= 60m^3

41) 6 ft × 6 ft ×6 ft = 36 ft × 6 ft = 216 ft^3

42) d=2r 10/2=5 r=5
3.14×5^2×14=78.5×14= 1099cm^3


43) 15=a×b/2 (area of trianlge)
15×12= 180in^3

44) c=2 (pi)r 8pi=2r (pi)
r=4
3.14×4^2×7=50.24×7=351.68

45) 24 ft^3 =2 ft × 3 ft × height
24=6×h
÷6 both sides
h=4ft

ANSWERED AT 17/10/2019 - 09:06 AM


QUESTION POSTED AT 17/10/2019 - 09:06 AM

Simplest form of 36/104

Well, A common factor between the two is 2. So dividing both by that factor would simplify it to 18/52 But since 4 is a greater but also a common factor, you can simplify the base fraction by a factor of four, resulting in 9/26

After that there is no way to simplify further, the most you can simplify 36/104 is 9/26

ANSWERED AT 17/10/2019 - 09:05 AM


QUESTION POSTED AT 17/10/2019 - 09:05 AM

Write an expression to show how many meters are equivalent to x centimeters

Y=meters
x=centimeters

Y=100x

ANSWERED AT 17/10/2019 - 09:05 AM


QUESTION POSTED AT 17/10/2019 - 09:05 AM

Show how many meters are equivalent to x centimeters

There are 0.01 meters per centimeter. This means if you have a problem like, "Tony measured his pencil and found it to be 37 centimeters; how many meters long is the pencil?" you can plug 0.01 into the equation. (0.01 * 37= 0.37). Thus, the pencil is 0.37meters. You can also do it backward if you need too; "Tony measured his pencil as saw it was 0.37 meters, how many centimeters long is the pencil?" ( 0.37 / 0.01= 37cm). I know this is a long explanation, does it help?

ANSWERED AT 17/10/2019 - 09:04 AM


QUESTION POSTED AT 17/10/2019 - 09:04 AM

Quadrilateral EFGH has coordinates E(a, a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of EF? Please show how the problem is done.

Answer:

The midpoints of the EF is (2a,a) .

Step-by-step explanation:

Definition of midpoints.

The midpoint is the point lie in middle of a line segment. It is equidistant from both endpoints .

Formula

Midpoints = (\frac{x_{2}+x_{1})}{2} ,\frac{(y_{2}+y_{1}}{2})

Quadrilateral EFGH has coordinates E(a, a), F(3a, a), G(2a, 0), and H(0, 0).

Now find out the midpoints of the  E(a, a) and F(3a, a) .

Midpoints\ of\ EF = (\frac{(3a+a)}{2} ,\frac{(a+a)}{2})

Midpoints\ of\ EF = (\frac{4a}{2} ,\frac{2a}{2})

Midpoints of EF = (2a,a)

Therefore the midpoints of the EF is (2a,a) .



ANSWERED AT 17/10/2019 - 09:01 AM


QUESTION POSTED AT 17/10/2019 - 09:01 AM

Solve the following inequality: 2(x + 1) – (–x + 5) ≤ –18. A. x ≤ –20 B. x ≤ –9 C. x ≤ –5 D. x ≤ –37

C.
You distribute both the 2 and the -, combine like terms, add three to both sides and then divide out the 3 from 3 on both sides

ANSWERED AT 17/10/2019 - 08:59 AM


QUESTION POSTED AT 17/10/2019 - 08:59 AM

Determine whether test point (-6,4) is a solution to the linear inequality x+y_<1

\bf \begin{array}{llll}&#10;-6&,&4\\&#10;\uparrow &&\uparrow \\&#10;x&&y&#10;\end{array}\qquad x+y\le 1\implies -6+4\le 1\implies -2\le 1

now, is it true that -2 is lesser than 1? if it's true, is a solution, if is false, is not then

ANSWERED AT 17/10/2019 - 08:58 AM


QUESTION POSTED AT 17/10/2019 - 08:58 AM

△GHJ is mapped to △G′H′J′ using each of the given rules. For which rules is △GHJ congruent to △G′H′J′? a) (x, y)→(8x, 8y) b) (x, y)→(x+8, y−8) c) (x, y)→(−x, y) d) (x, y)→(0.8x, 0.8y) e) (x, y)→(−x, −y)

I'm not sure if this question is supposed to have a corresponding image. However, in dealing with congruence of an image to its pre-image, we simply need to determine whether the original image was resized or not.

Congruent images are images that are equal in measure. This will only result if the pre-image is a result of reflection, rotation, or translation.

(x, y)→(−x, y) ⇒ reflection

(x, y)→(−x, −y) 
⇒ rotation

(x, y)→(x+8, y−8) ⇒ translation

ANSWERED AT 17/10/2019 - 08:58 AM


QUESTION POSTED AT 17/10/2019 - 08:58 AM

Determine the domain of the function h(x)= 8x/x(x^2-81)

H(x) = (8x)/x(x^2 - 81)
hx = 2^3(x^2 - 81)
hx = 2^3 • x^2 - 2^3 • 81

ANSWERED AT 17/10/2019 - 08:57 AM


QUESTION POSTED AT 17/10/2019 - 08:57 AM

The cost of renting a canoe is $8 for the first hour plus another $3 for each additional hour. Which of the following represents this situation, where C is the total cost of renting a canoe for h hours?

Answer:

C(h)=3h+5

Step-by-step explanation:

Let

h-----> the number of hours

C-----> the cost of renting a canoe

we know that

C(h)=8+3(h-1)

C(h)=8+3h-3

C(h)=3h+5 ------> equation that represent the situation

ANSWERED AT 17/10/2019 - 08:56 AM


QUESTION POSTED AT 17/10/2019 - 08:55 AM

Given the following constants for a standard form quadratic equation, determine the nature of its roots.

ax^2+bx+c=0
3x^2+3x+2=0
D=b^2-4ac=3^2-4*3*2=9-24=-15
D<0, so there are no real solutions.

ANSWERED AT 17/10/2019 - 08:55 AM


QUESTION POSTED AT 17/10/2019 - 08:55 AM

Staci has 8 3/8 liters of paint and uses 5 3/4 liters of it. How much paint does Staci have left? Give your answer in simplest form.

We will use subtraction to solve this. We will subtract 5 3/4 from 8 3/8, because we must take away the amount she used. 

8 3/8 - 5 3/4

The easiest way to solve this is to convert to fractions. 

67/8 - 23/4

We must create common denominators to solve this. We will multiply both 23 and 4 from the second fraction by 2 to get to a common denominator of 8. 

67/8 - 46/8 = 21/8

We will then convert this fraction back to a mixed number. 

21/8 = 2 5/8

2 5/8 liters is our final answer

ANSWERED AT 17/10/2019 - 08:52 AM


QUESTION POSTED AT 17/10/2019 - 08:52 AM

Ralph is 3 times as old as Sara. In 6 years, Ralph will be only twice as old as Sara will be then. Find Ralph's age now.If x represents Sarah's age now, which of the following expressions represents Ralph's age in six years?

X years  -  Sara (now)
3x years  -  Ralph (now) 

(x + 6)  -  Sara (in 6 years)
(3x + 6)  -  Ralph (in 6 years)

1) 3x + 6 = (x + 6) * 2
    3x + 6 = 2x + 12
    3x - 2x = 12 - 6
    x = 6 years - Sara (now)
2) 6 * 3 = 18 years - Ralph (now)

In 6 years :
6 + 6 = 12 - Sara
18 + 6 = 24 - Ralph
24 : 12 = 2 - twice as old as Sara/

ANSWERED AT 17/10/2019 - 08:51 AM


QUESTION POSTED AT 17/10/2019 - 08:51 AM

Point G lies between points F and H on . If the length of FH is 18 units, what is the value of x? 3 4 5 6

see the attached figure to better understand the problem

we know that

FH=FG+GH

FH=18 -------> equation 1

FH=4x+2x

FH=6x -------> equation 2

equate equation 1 and equation 2

18=6x

x=3

therefore

the answer is

x=3

ANSWERED AT 17/10/2019 - 08:49 AM


QUESTION POSTED AT 17/10/2019 - 08:49 AM

How many regular hexagons meet at a vertex to form a regular tessellation?

I think it should be 3 I'm not 100% sure

ANSWERED AT 17/10/2019 - 08:48 AM


QUESTION POSTED AT 17/10/2019 - 08:48 AM

Somebody help me please???????? Staci has 8 3/8 liters of paint and uses 5 3/4 liters of it. How much paint does Staci have left? Give your answer in simplest form.

 \frac{3}{8} - 5  \frac{3}{4} = 8  \frac{3}{8}  - 5  \frac{6}{8} = 7  \frac{11}{8} - 5  \frac{6}{8} =  \frac{5}{8} liters = 2,625 litres - answer. 

ANSWERED AT 17/10/2019 - 08:48 AM


QUESTION POSTED AT 17/10/2019 - 08:48 AM

How many regular hexagons meet at a vertex to form a regular tessellation? 2 3 4 6

Answer: yesss answe to this world this woulr be 3

Step-by-step explanation:

ANSWERED AT 17/10/2019 - 08:48 AM


QUESTION POSTED AT 17/10/2019 - 08:48 AM

Which of the following represents the zeros of f(x) = x3 − 12x2 + 47x − 60

Answer: x=3,\:x=4,\:x=5.


Step-by-step explanation: Given polynomial function f(x) = x^3-12x^2+47x-60.

\mathrm{Use\:the\:rational\:root\:theorem}\\

p=60,\:\quad q=1

\mathrm{The\:dividers\:of\:}p:\quad 1,\:2,\:3,\:4,\:5,\:6,\:10,\:12,\:15,\:20,\:30,\:60,\:\quad \mathrm{The\:dividers\:of\:}q:\quad 1

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:4,\:5,\:6,\:10,\:12,\:15,\:20,\:30,\:60}{1}

\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x-3

\frac{x^3-12x^2+47x-60}{x-3}=x^2-9x+20 \ \  By \ long \ division.

\mathrm{Factor}\:x^2-9x+20:\quad \left(x-4\right)\left(x-5\right)

Therefore,

x^3-12x^2+47x-60=\left(x-3\right)\left(x-4\right)\left(x-5\right)

\mathrm{Solve\:}\:x-3=0:\quad x=3

\mathrm{Solve\:}\:x-4=0:\quad x=4

\mathrm{Solve\:}\:x-5=0:\quad x=5

\mathrm{The\:final\:solutions\:to\:the\:equation\:are:}

x=3,\:x=4,\:x=5

ANSWERED AT 17/10/2019 - 08:47 AM


QUESTION POSTED AT 17/10/2019 - 08:47 AM