# How do you solve -2(6x+3)=-27–5x ?

QUESTION POSTED AT 02/12/2019 - 07:56 AM

QUESTION POSTED AT 02/12/2019 - 07:56 AM

Hi!

Our goal is to isolate x on one side by doing the same operation on both sides.

**First let's use the distribution property.**

-2 x 6 = -12

-2 x 3 = -6

-12x - 6 = -27 - 5x

**Add 6 to both sides**

-12x - 6 + 6 = -27 + 6 - 5x

-12x = -21 - 5x

**Add 5x to both sides**

-12x + 5x = -21 - 5x + 5x

-7x = -21

**Divide by -7 on both sides**

-7x/-7 = -21/-7

x = 3

The answer is**x = 3**

Hope this helps! :)

Our goal is to isolate x on one side by doing the same operation on both sides.

-2 x 6 = -12

-2 x 3 = -6

-12x - 6 = -27 - 5x

-12x - 6 + 6 = -27 + 6 - 5x

-12x = -21 - 5x

-12x + 5x = -21 - 5x + 5x

-7x = -21

-7x/-7 = -21/-7

x = 3

The answer is