+12x +12x

72=32+11x

-32 -32

40=11x

/11 /11

x= 40/11 or 3.63 (repeating)

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Answered @ 19/08/2019 05:54 PM By answersmine

72-12x=32-x

+12x +12x

72=32+11x

-32 -32

40=11x

/11 /11

x= 40/11 or 3.63 (repeating)

+12x +12x

72=32+11x

-32 -32

40=11x

/11 /11

x= 40/11 or 3.63 (repeating)

Hope this helps.

r3t40

65/65 x= 20/65

X= 0.307692307692308

X= 0.307692307692308

**Answer:**

3y² -2y -1 =0

**Step-by-step explanation:**

X= y²+1 .....(1)

3x - 2y = 4.....(2)

put x in (2) : 3(y²+1 )-2y =4

3y² +3 -2y -4 = 0

3y² -2y -1 =0

**Answer:**

X=3.5

**Step-by-step explanation:**

Answer:

1. $60

2. $240

Step-by-step explanation:

Use the formula for simple interest. Put your numbers in the formula and do the arithmetic.

i = Prt . . . . where i is the interest amount, P is the principal, r is the rate, t is the time period

1. P = $600, r = 0.05, t = 2, so you have ...

i = $600·0.05·2 = $60

__

2. P = $1500, r = 0.04, t = 4, so you have ...

i = $1500·0.04·4 = $240

**Answer:**

**Step-by-step explanation:**

**Question 1:**

For this case we must simplify the following expression:

We factor the numerator of the expression, looking for two numbers that when multiplied give as a result 2 and when summed give as result 3. These numbers are 2 and 1.

So:

Rewriting the expression we have:

Simplifying common terms in the numerator and denominator, we have that the expression is reduced to:

**ANswer:**

**Option A**

**Question 2:**

For this case we must find the value of the variable "x" of the following expression:

Multiplying by 12 on both sides of the equation we have:

We add 1 to both sides of the equation:

**ANswer:**

**Option A**

**Question 3:**

For this case we must find the domain of the following function:

The domain of a function is given by all the values for which the function is defined.

The given function is not defined when the denominator is 0.

Thus, the domain is given by all real numbers except 2.

**Answer:**

**OPTION C**

**Question 4:**

For this case we must simplify the following expression:

We take common factor 3 from the numerator of the expression:

We can write 6 as

Rewriting the expression we have:

Simplifying common terms of the numerator and denominator we have that the expression is reduced to:

**ANswer:**

**Option D**

**Question 5:**

For this case we must find the vertical asymptotes of the following function:

We have by definition, that the vertical asymptotes are vertical lines to which the function is approaching indefinitely without ever cutting them.

To locate the vertical asymptotes in rational functions, we find the values of "x" that annul the denominator, but not the numerator.

So:

We factor the denominator, looking for two numbers that when multiplied by -2 and when added together give 1. Thus:

Now, equaling the denominator to zero, we have that the vertical asymptote occurs in areas of infinite discontinuity of:

**Answer:**

**Option C**

**Question 6:**

For this case we must find the discontinuities and zeros of the following function:

We have by definition, that if a function is not continuous at a point, it is said that the function has a discontinuity at that point and that the function is discontinuous.

The function is undefined where the denominator equals 0.

It is a discontinuity.

Now, we factor the numerator looking for two numbers that multiplied by 6 and added by 5. These numbers are 3 and 2. Then:

Now we find the zeros of the funicon, for that we replace f (x) with y.

We eliminate common terms from the numerator and denominator.

To find the roots, we do y = 0:

**ANswer:**

**Option B**

**Question 7:**

For this case we must find the discontinuities and zeros of the following function:

We have by definition, that if a function is not continuous at a point, it is said that the function has a discontinuity at that point and that the function is discontinuous.

The function is undefined where the denominator equals 0. Then:

The function is discontinuous for and

Now factoring the denominator we have:

(x-3) (x + 3)

To find the zeros of the function we change f (x) by y.

We make y = 0:

So, the zeros of the function are at

**ANswer:**

**The function is discontinuous for and **

**The zeros of the function are at **

**Question 8:**

For this case we have:

x: Variable representing red fish

y: Variable representing blue fish

They tell us that:

Then, we substitute the second equation in the first one;

So, there are 20 blue fish.

**Answer:**

**20 blue**

ANSWER

D. 33

EXPLANATION

The given radical equation is

Group similar terms,

Square both sides:

Simplify

Solve for x

**Answer: Second option.**

**Step-by-step explanation:**

Let be "e" the number of easy puzzles Tina solved and "h" the number of hard puzzles Tina solved.

Set up a system of equations:

You can use the Eliminationn Method to solve this system of equations:

- Multiply the first equation by -30.
- Add the equations.
- Solve for "h".

Therefore, through this proccedure, you get:

**Answer:**

The answer is 1/4.