# Speed of a car that travels 180 km in 3.00 hrs

QUESTION POSTED AT 19/08/2019 - 05:54 PM

QUESTION POSTED AT 19/08/2019 - 05:54 PM

The metric system is quite logical compared to your imperial system I must say, all you gotta do is to divide the distance driven by the amount of hours it took. 180/3 = 60. Average speed of a car that does 180km in 3 hours is 60 kmph which is 37.28 mph.✌️

You do it by pointing out that 'acceleration' does NOT mean speeding up.

"Acceleration" means ANY change in the motion, whether it's

speeding up, slowing down, or changing direction.

If a driver wants to stay on the circular track and not run off into the bushes,

then he has to keep changing the DIRECTION of the car's motion.

"Acceleration" means ANY change in the motion, whether it's

speeding up, slowing down, or changing direction.

If a driver wants to stay on the circular track and not run off into the bushes,

then he has to keep changing the DIRECTION of the car's motion.

ANSWERED AT 23/09/2019 - 04:21 AM

QUESTION POSTED AT 23/09/2019 - 04:21 AM

it is actually c because the acceleration is the change in velocity so the car is experiencing a change in velocity and it is accelerating.

ANSWERED AT 23/09/2019 - 04:18 AM

QUESTION POSTED AT 23/09/2019 - 04:18 AM

The average speed of the car is

(the mile marker he passes at the end of the 1.75 h) minus 115

divided by

(1.75 hours) .

The unit is 'miles per hour'.

(the mile marker he passes at the end of the 1.75 h) minus 115

divided by

(1.75 hours) .

The unit is 'miles per hour'.

ANSWERED AT 23/09/2019 - 04:12 AM

QUESTION POSTED AT 23/09/2019 - 04:12 AM

KE=m. Plug your velocity in, ignoring the rest of the formula.

= ?

=?

= ?

=?

ANSWERED AT 23/09/2019 - 03:44 AM

QUESTION POSTED AT 23/09/2019 - 03:44 AM

We know that KE=9J and the Mass (m) = 1kg. The formula to find this is going to be our Kinetic Energy Equation. K=m. But we will rearrange it to find the veloctiy so it looks like this: v=. Then just plug in the variables and solve.

ANSWERED AT 23/09/2019 - 03:43 AM

QUESTION POSTED AT 23/09/2019 - 03:43 AM

Speed = (distance) / (time)

= (4 meters) / (5 seconds)

= (4/5) meters/second

= 0.8 meters/second (choice-B)

ANSWERED AT 23/09/2019 - 03:34 AM

QUESTION POSTED AT 23/09/2019 - 03:34 AM

It's speed will also increase 'cause speed is directly proportional to Kinetic Energy.

ANSWERED AT 23/09/2019 - 03:34 AM

QUESTION POSTED AT 23/09/2019 - 03:34 AM

Speed is the **RATE** of change of an object's position over time.

ANSWERED AT 23/09/2019 - 03:14 AM

QUESTION POSTED AT 23/09/2019 - 03:14 AM

1. I don't see a graph

2. It could be because a liquid could be evaporating in the process

3. It could be that the liquid is getting colder

4. 1 liquid is medium and moving a the normal pace

2. It could be because a liquid could be evaporating in the process

3. It could be that the liquid is getting colder

4. 1 liquid is medium and moving a the normal pace

ANSWERED AT 23/09/2019 - 03:05 AM

QUESTION POSTED AT 23/09/2019 - 03:05 AM

**Answer:**

The acceleration of the car is 1.25 m/s².

**Explanation:**

**Given that,**

Initial velocity = 15 m/s

Final velocity= 30 m/s

Time t = 12 sec

**We need to calculate the acceleration of the car**

**Using equation of motion**

Where, v = final velocity

u - initial velocity

t = time

Put the value in the equation

**Hence, The acceleration of the car is 1.25 m/s².**

ANSWERED AT 23/09/2019 - 02:57 AM

QUESTION POSTED AT 23/09/2019 - 02:57 AM

the speed of sound in air is directly proportional to the temperature of the air. The speed of sound depends on the temperature of the surrounding air, this can be represented by a speed of sound in air formula: v = 331m/s + 0.6m/s/C * T (where T is temperature)

ANSWERED AT 23/09/2019 - 02:49 AM

QUESTION POSTED AT 23/09/2019 - 02:49 AM

The Correct Answer Is **Friction.**

ANSWERED AT 23/09/2019 - 02:42 AM

QUESTION POSTED AT 23/09/2019 - 02:42 AM

Velocity, acceleration, force, momentum,

ANSWERED AT 23/09/2019 - 02:08 AM

QUESTION POSTED AT 23/09/2019 - 02:08 AM

I believe your answer will be 5.2 meters

ANSWERED AT 23/09/2019 - 01:51 AM

QUESTION POSTED AT 23/09/2019 - 01:51 AM

The normal is a line perpendicular (forming a 90 degree angle) to the boundary between the two substances. The bending occurs because light travels more slowly in a denser medium.

ANSWERED AT 23/09/2019 - 01:20 AM

QUESTION POSTED AT 23/09/2019 - 01:20 AM

-- An A300 Airbus commercial jet airliner, loaded with passengers, cargo,

and flight crew, cruising in a straight line, at 35,000 ft altitude, at a constant

speed of 530 miles per hour.

and flight crew, cruising in a straight line, at 35,000 ft altitude, at a constant

speed of 530 miles per hour.

ANSWERED AT 23/09/2019 - 01:16 AM

QUESTION POSTED AT 23/09/2019 - 01:16 AM

(0.20 km/minute) · (60 min/hour) · (2.5 hours)

= (0.20 · 60 · 2.5) km·min·hour / min·hour

=

=

ANSWERED AT 23/09/2019 - 01:13 AM

QUESTION POSTED AT 23/09/2019 - 01:12 AM

Whenever particle does straight line motion, Distance = speed x time
=3.5 x 1500
=5250 km or 5250000 meters.
Hope it helped you :-D

ANSWERED AT 23/09/2019 - 01:12 AM

QUESTION POSTED AT 23/09/2019 - 01:12 AM

Using the equation v(average)=x traveled/time

v = 100/2.5

You get 40 kilometers per hour

Hope this helped!

v = 100/2.5

You get 40 kilometers per hour

Hope this helped!

ANSWERED AT 23/09/2019 - 01:12 AM

QUESTION POSTED AT 23/09/2019 - 01:12 AM

As ur bottle cools down in the car it will slowly collaps into its self like a giant hand is crushing it from the outside of the bottle and when the bottle reaches the same air as the outside of the bottle

ANSWERED AT 23/09/2019 - 01:01 AM

QUESTION POSTED AT 23/09/2019 - 01:01 AM

The magnitude of the force applied by car on the truck is .

**Further Explanation:**

The car applies a force on the ground due to which the truck moves in the positive x direction. The friction force between the tires of the truck and ground oppose the external force applied by the car. Therefore, the net force on the car truck system is the difference between the force applied by the car on the ground and the friction force on the tires of the truck and it is acting along the direction of motion of the car.

**Given:**

The mass of the car is .

The mass of the truck is .

The force with which the car pushes the ground is .

The friction force between the tires of the truck and ground is .

**Concept:**

The net force on the car truck system is defined as the product of net mass of the system i.e., sum of mass of car and mass of truck and the acceleration with which the system is moving.

The net force on the car truck system is:

Rearrange the above expression.

…… (1)

Here, is the net force on the car truck system, is the mass of the car, is the mass of the truck and is the acceleration with which the system is moving.

The net force on the car truck system is:

…… (2)

Here, is the force with which the car pushes the ground and is the friction force between the truck tires and ground.

The force applied by the car on the truck is:

Rearrange the above expression.

…… (3)

Here, is the force applied by car on truck.

Substitute the values of and f in equation (2).

Substitute the value of , and in equation (1).

Substitute the values of , and in equation (3).

Thus, the magnitude of the force applied by car on the truck is .

**Learn more:**

1. Change in momentum of a car brainly.com/question/9484203

2. Maximum velocity of a ball brainly.com/question/11023695

3. The motion of a body under friction brainly.com/question/4033012

**Answer Details:**

**Grade:** High School

**Subject:** Physics

**Chapter:** Kinematics

**Keywords:**

Motion, force, friction force, car, truck, force applied by car on truck, force applied by truck on car, acceleration, 3105.2 N, 3105 N, 3105.2 newton, 3105 newton, 3105.2 Newton, 3105 Newton.

ANSWERED AT 23/09/2019 - 12:46 AM

QUESTION POSTED AT 23/09/2019 - 12:46 AM

**Answer: option c: v₀ = v₂ > v₁ > 0**

**Explanation:**

1) **Velocity** is the rate of change of the position with time. Therefore, in a graph of position vs time, the velocity is the **slope of the path that describes the motion.**

2) In this case you are requested to compare the **speeds**, i.e. just the **magnitudes of the velocities.** You can perform that by **comparing the slopes **in the three positions (x₀, y₀), (x₁, y₁), and (x₂, y₂).

3) Regarding **v₁**, since it corresponds to the **peak of the curve (x₁.y₁),** the vertical component of the velocity is zero (the horizontal component is constant, since there is not any horizontal force acting), so at this point the speed reaches its minimum value, then **v₁ > 0, and v₁ is less than any other speed.**

4) Regarding **v₀ and v₂**, at (x₀, y₀) and (x₂, y₂), note that those are points at the same distance from the axis of symmetry of the curve (assuming it is **perfect parabola**, which is what the graph intends to show).

That means that the **velocities at those points are equal in magnitude** but opposite in signs. Since, you are asked about the **speed**, which is magnitude, you conclude **v₀ = v₂**.

In **conclusion v₀ = v₂ > v₁ > 0, which is the option c.**

ANSWERED AT 23/09/2019 - 12:37 AM

QUESTION POSTED AT 23/09/2019 - 12:37 AM

In my opinion the graph of the three functions would be as follows:

Graph A

its j3rk

Graph B

its acceleration

Graph C

the velocity of the car

Graph D

the position function of a car

Hope this answers the question. Have a nice day.

Graph A

its j3rk

Graph B

its acceleration

Graph C

the velocity of the car

Graph D

the position function of a car

Hope this answers the question. Have a nice day.

ANSWERED AT 23/09/2019 - 12:33 AM

QUESTION POSTED AT 23/09/2019 - 12:33 AM

C) Weight is correct. The force of gravity acting upon anything is weight.

A) mass is how much stuff is in something

B) relates to freefall, after the resistance in the air prevents any acceleration

D) freefall=object falling

A) mass is how much stuff is in something

B) relates to freefall, after the resistance in the air prevents any acceleration

D) freefall=object falling

ANSWERED AT 23/09/2019 - 12:26 AM

QUESTION POSTED AT 23/09/2019 - 12:26 AM

Terminal velocity is the correct answer

ANSWERED AT 23/09/2019 - 12:25 AM

QUESTION POSTED AT 23/09/2019 - 12:25 AM

I agree with kingofthe818

ANSWERED AT 23/09/2019 - 12:14 AM

QUESTION POSTED AT 23/09/2019 - 12:14 AM

Below are the choices that can be found in the other sources:

A. diffraction

B. refraction

C. reflection

D. transmission

The answer is diffraction. It means that the process by which a beam of light or other system of waves is spread out as a result of passing through a narrow aperture or across an edge, typically accompanied by interference between the wave forms produced.

A. diffraction

B. refraction

C. reflection

D. transmission

The answer is diffraction. It means that the process by which a beam of light or other system of waves is spread out as a result of passing through a narrow aperture or across an edge, typically accompanied by interference between the wave forms produced.

ANSWERED AT 22/09/2019 - 11:54 PM

QUESTION POSTED AT 22/09/2019 - 11:54 PM

MA = Mechanical advantage of car jack = 6

= Output force required to raise the car = 600 N

= Input force required to raise the car = ?

Mechanical advantage is given as

MA = /

inserting the values

6 = 600/

= 600/6

= 100 N

Hence the input force required comes out to be 100 N

ANSWERED AT 22/09/2019 - 11:53 PM

QUESTION POSTED AT 22/09/2019 - 11:53 PM

I am not sure but i guess it is B or d i am leaning towards D though. Sorry not that good with mechanical stuff.

ANSWERED AT 22/09/2019 - 11:52 PM

QUESTION POSTED AT 22/09/2019 - 11:52 PM

-- Equations #2 and #6 are both the same equation,

and are both correct.

-- If you divide each side by 'wavelength', you get Equation #4,

which is also correct.

-- If you divide each side by 'frequency', you get Equation #3,

which is also correct.

With some work, you can rearrange this one and use it to calculate

frequency.

**Summary:**

-- Equations #2, #3, #4, and #6 are all correct statements,

and can be used to find frequency.

-- Equations #1 and #5 are incorrect statements.

and are both correct.

-- If you divide each side by 'wavelength', you get Equation #4,

which is also correct.

-- If you divide each side by 'frequency', you get Equation #3,

which is also correct.

With some work, you can rearrange this one and use it to calculate

frequency.

-- Equations #2, #3, #4, and #6 are all correct statements,

and can be used to find frequency.

-- Equations #1 and #5 are incorrect statements.

ANSWERED AT 22/09/2019 - 11:51 PM

QUESTION POSTED AT 22/09/2019 - 11:51 PM