Speed of a car that travels 180 km in 3.00 hrs

QUESTION POSTED AT 19/08/2019 - 05:54 PM

Answered by answersmine AT 19/08/2019 - 05:54 PM

The metric system is quite logical compared to your imperial system I must say, all you gotta do is to divide the distance driven by the amount of hours it took. 180/3 = 60. Average speed of a car that does 180km in 3 hours is 60 kmph which is 37.28 mph.✌️
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ANSWERED AT 23/09/2019 - 04:21 AM


QUESTION POSTED AT 23/09/2019 - 04:21 AM

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The average speed of the car is

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ANSWERED AT 23/09/2019 - 04:12 AM


QUESTION POSTED AT 23/09/2019 - 04:12 AM

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ANSWERED AT 23/09/2019 - 03:44 AM


QUESTION POSTED AT 23/09/2019 - 03:44 AM

A 1 kilogram ball has 8joules of kinetic energy what is its speed

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ANSWERED AT 23/09/2019 - 03:43 AM


QUESTION POSTED AT 23/09/2019 - 03:43 AM

If a basketball travels a distance of 4 meters in 5 seconds, what is its average speed? A. 4 meters/ second B. 0.8 meters/second C. 1.2 meters/second D. 5 meters/second


             Speed  =  (distance)  /  (time)

                         =  (4 meters)  /  (5 seconds)

                         =     (4/5)      meters/second

                         =      0.8 meters/second        (choice-B)

ANSWERED AT 23/09/2019 - 03:34 AM


QUESTION POSTED AT 23/09/2019 - 03:34 AM

If energy is transferred to an object's kinetic energy store, what happens to its speed?

It's speed will also increase 'cause speed is directly proportional to Kinetic Energy.

ANSWERED AT 23/09/2019 - 03:34 AM


QUESTION POSTED AT 23/09/2019 - 03:34 AM

What does speed measure? A. change of an objects position over time.B. the distance between two positions of an object at different points in time

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ANSWERED AT 23/09/2019 - 03:14 AM


QUESTION POSTED AT 23/09/2019 - 03:14 AM

The graph shows that the molecules in a liquid do not all have the same speed

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ANSWERED AT 23/09/2019 - 03:05 AM


QUESTION POSTED AT 23/09/2019 - 03:05 AM

A car speeds up from 15 m/s to 30 m/s in 12 seconds. What is the acceleration of the car?

Answer:

The acceleration of the car is 1.25 m/s².

Explanation:

Given that,

Initial velocity = 15 m/s

Final velocity= 30 m/s

Time t = 12 sec

We need to calculate the acceleration of the car

Using equation of motion

v = u+at

a =\dfrac{v-u}{t}

Where, v = final velocity

u - initial velocity

t = time

Put the value in the equation

a =\dfrac{30-15}{12}

a=\dfrac{15}{12}

a =1.25\ m/s^2

Hence, The acceleration of the car is 1.25 m/s².

ANSWERED AT 23/09/2019 - 02:57 AM


QUESTION POSTED AT 23/09/2019 - 02:57 AM

Which statement is true? The speed of sound in air is inversely proportional to the temperature of the air. The speed of sound in air is directly proportional to the temperature of the air. The speed of sound in air is twice the temperature of the air. The speed of sound in air is not affected by the temperature of the air.

 the speed of sound in air is directly proportional to the temperature of the air. The speed of sound depends on the temperature of the surrounding air, this can be represented by a speed of sound in air formula: v = 331m/s + 0.6m/s/C * T (where T is temperature)

ANSWERED AT 23/09/2019 - 02:49 AM


QUESTION POSTED AT 23/09/2019 - 02:49 AM

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ANSWERED AT 23/09/2019 - 02:42 AM


QUESTION POSTED AT 23/09/2019 - 02:42 AM

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ANSWERED AT 23/09/2019 - 02:08 AM


QUESTION POSTED AT 23/09/2019 - 02:08 AM

Average speed of a runner runs 500 .o min. 1.6 min is

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ANSWERED AT 23/09/2019 - 01:51 AM


QUESTION POSTED AT 23/09/2019 - 01:51 AM

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The normal is a line perpendicular (forming a 90 degree angle) to the boundary between the two substances. The bending occurs because light travels more slowly in a denser medium.

ANSWERED AT 23/09/2019 - 01:20 AM


QUESTION POSTED AT 23/09/2019 - 01:20 AM

What is an example of traveling at a high velocity but a slow acceleration

-- An A300 Airbus commercial jet airliner, loaded with passengers, cargo,
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ANSWERED AT 23/09/2019 - 01:16 AM


QUESTION POSTED AT 23/09/2019 - 01:16 AM

A boy is pedaling his bicycle at a velocity of 0.20km/ minute . How far will he travel in 2.5 hours


           (0.20 km/minute) · (60 min/hour) · (2.5 hours)

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       =          30 km .

      
      = 

ANSWERED AT 23/09/2019 - 01:13 AM


QUESTION POSTED AT 23/09/2019 - 01:12 AM

A plane is traveling for 3.5 hours at a velocity 1,500 km/h. What distance did it travel?

Whenever particle does straight line motion, Distance = speed x time =3.5 x 1500 =5250 km or 5250000 meters. Hope it helped you :-D

ANSWERED AT 23/09/2019 - 01:12 AM


QUESTION POSTED AT 23/09/2019 - 01:12 AM

What is the velocity of a car that traveled a total of 100 kilometers south in 2.5 hours?

Using the equation v(average)=x traveled/time
v = 100/2.5
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Hope this helped!

ANSWERED AT 23/09/2019 - 01:12 AM


QUESTION POSTED AT 23/09/2019 - 01:12 AM

Why will an empty water bottle contract in a cold car overnight, only if the lid is on?

As ur bottle cools down in the car it will slowly collaps into its self like a giant hand is crushing it from the outside of the bottle and when the bottle reaches the same air as the outside of the bottle

ANSWERED AT 23/09/2019 - 01:01 AM


QUESTION POSTED AT 23/09/2019 - 01:01 AM

A 1230kg car pushes a 2160kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 4590N . Take the friction between the truck's tires and the ground to be 470N . What is the magnitude F_ConT of the force that the car exerts on the truck? Use the coordinate system shown in Part B, where upward is the positive y direction and to the right, the direction F_ConT points, is the positive x direction.

The magnitude of the force applied by car on the truck is \fbox{\begin\\3105.2\,{\text{N}}\end{minispace}}.

Further Explanation:

The car applies a force on the ground due to which the truck moves in the positive x direction. The friction force between the tires of the truck and ground oppose the external force applied by the car. Therefore, the net force on the car truck system is the difference between the force applied by the car on the ground and the friction force on the tires of the truck and it is acting along the direction of motion of the car.

Given:

The mass of the car is 1230\,{\text{kg}}.

The mass of the truck is 2160\,{\text{kg}}.

The force with which the car pushes the ground is 4590\,{\text{N}}.

The friction force between the tires of the truck and ground is 470\,{\text{N}}.

Concept:

The net force on the car truck system is defined as the product of net mass of the system i.e., sum of mass of car and mass of truck and the acceleration with which the system is moving.

The net force on the car truck system is:

{F_{net}} = \left( {{m_C} + {m_T}} \right)a

Rearrange the above expression.

a=\dfrac{{{F_{net}}}}{{\left( {{m_C} + {m_T}} \right)}}                                             …… (1)

Here, {F_{net}} is the net force on the car truck system, {m_C} is the mass of the car, {m_T} is the mass of the truck and a is the acceleration with which the system is moving.

The net force on the car truck system is:

{F_{net}} = {F_C} - f                                                                               …… (2)

Here, {F_C} is the force with which the car pushes the ground and f is the friction force between the truck tires and ground.

The force applied by the car on the truck is:

{F_{C\,on\,T}} - f = {m_T}\text{ a}  

Rearrange the above expression.

{F_{C\,on\,T}} = {m_T}\text{ a}+f                                                                                …… (3)

Here, {F_{C\,on\,T}} is the force applied by car on truck.

Substitute the values of {F_C} and f in equation (2).

\begin{aligned}{F_{net}}&=4590\,{\text{N}} - 470\,{\text{N}}\\&=4120\,{\text{N}}\\\end{aligned}

Substitute the value of {F_{net}}, {m_C} and {m_T} in equation (1).

\begin{aligned}a&=\frac{{4120\,{\text{N}}}}{{\left( {1230\,{\text{kg}} + 2160\,{\text{kg}}} \right)}} \\&=1.22\,{{\text{m}}\mathord{\left/ {\vphantom {{\text{m}} {{{\text{s}}^{\text{2}}}}}} \right.\kern-\nulldelimiterspace} {{{\text{s}}^{\text{2}}}}} \\\end{aligned}

Substitute the values of {m_T}, a and f in equation (3).

\begin{aligned}{F_{C\,on\,T}}&=\left( {2160\,{\text{kg}}} \right)\left( {1.22\,{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {{{\text{s}}^{\text{2}}}}}} \right.\kern-\nulldelimiterspace} {{{\text{s}}^{\text{2}}}}}} \right)+\left( {470\,{\text{N}}} \right)\\&=3105.2\,{\text{N}} \\ \end{aligned}

Thus, the magnitude of the force applied by car on the truck is \fbox{\begin\\3105.2\,{\text{N}}\end{minispace}}.

Learn more:

1. Change in momentum of a car  brainly.com/question/9484203

2.  Maximum velocity of a ball brainly.com/question/11023695

3. The motion of a body under friction brainly.com/question/4033012

Answer Details:

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords:

Motion, force, friction force, car, truck, force applied by car on truck, force applied by truck on car, acceleration, 3105.2 N, 3105 N, 3105.2 newton, 3105 newton, 3105.2 Newton, 3105 Newton.

ANSWERED AT 23/09/2019 - 12:46 AM


QUESTION POSTED AT 23/09/2019 - 12:46 AM

How do the speeds v0, v1, and v2 (at times t0, t1, and t2) compare? a: v0 = v1 = v2 > 0 b: v0 = v2 > v1 = 0 c: v0 = v2 > v1 > 0 d: v0 > v1 > v2 > 0 e: v0 > v2 > v1 = 0

Answer: option c: v₀ = v₂ > v₁ > 0

Explanation:

1) Velocity is the rate of change of the position with time. Therefore, in a graph of position vs time, the velocity is the slope of the path that describes the motion.

2) In this case you are requested to compare the speeds, i.e. just the magnitudes of the velocities. You can perform that by comparing the slopes in the three positions (x₀, y₀), (x₁, y₁), and (x₂, y₂).

3) Regarding v₁, since it corresponds to the peak of the curve (x₁.y₁), the vertical component of the velocity is zero (the horizontal component is constant, since there is not any horizontal force acting), so at this point the speed reaches its minimum value, then v₁ > 0, and v₁ is less than any other speed.

4) Regarding v₀ and v₂, at (x₀, y₀) and (x₂, y₂), note that those are points at the same distance from the axis of symmetry of the curve (assuming it is perfect parabola, which is what the graph intends to show).

That means that the velocities at those points are equal in magnitude but opposite in signs. Since, you are asked about the speed, which is magnitude, you conclude v₀ = v₂.

In conclusion v₀ = v₂ > v₁ > 0, which is the option c.

ANSWERED AT 23/09/2019 - 12:37 AM


QUESTION POSTED AT 23/09/2019 - 12:37 AM

The figure shows the graphs of three functions. One is the position function of a car, one is the velocity of the car, one is its acceleration, and one is its j3rk. Identify each curve.

In my opinion the graph of the three functions would be as follows:

Graph A 
its j3rk

Graph B
its acceleration

Graph C
the velocity of the car

Graph D 
the position function of a car

Hope this answers the question. Have a nice day.

ANSWERED AT 23/09/2019 - 12:33 AM


QUESTION POSTED AT 23/09/2019 - 12:33 AM

The force of gravity on a car driving on the surface of a planet is called A.) Mass B.) Terminal Velocity C.) Weight D.) Freefall

C) Weight is correct. The force of gravity acting upon anything is weight. 
A) mass is how much stuff is in something
B) relates to freefall, after the resistance in the air prevents any acceleration
D) freefall=object falling

ANSWERED AT 23/09/2019 - 12:26 AM


QUESTION POSTED AT 23/09/2019 - 12:26 AM

The force of gravity on a car driving on a planet is called

Terminal velocity is the correct answer

ANSWERED AT 23/09/2019 - 12:25 AM


QUESTION POSTED AT 23/09/2019 - 12:25 AM

This law is evident when your riding in a car without a seat belt and the car stops suddenly you continue to move forward

I agree with kingofthe818

ANSWERED AT 23/09/2019 - 12:14 AM


QUESTION POSTED AT 23/09/2019 - 12:14 AM

In a harbor, you can see sea waves traveling around the edges of small stationary boats. Why does this happen?

Below are the choices that can be found in the other sources:

A. diffraction 
B. refraction 
C. reflection 
D. transmission

The answer is diffraction. It means that the process by which a beam of light or other system of waves is spread out as a result of passing through a narrow aperture or across an edge, typically accompanied by interference between the wave forms produced.

ANSWERED AT 22/09/2019 - 11:54 PM


QUESTION POSTED AT 22/09/2019 - 11:54 PM

A car jack with a mechanical advantage of 6 needs to produce an output force of 600 N to raise a car. What input force is required?

MA = Mechanical advantage of car jack = 6

F_{o} = Output force required to raise the car = 600 N

F_{i} = Input force required to raise the car = ?

Mechanical advantage is given as

MA = F_{o} /F_{i}

inserting the values

6 = 600/F_{i}

F_{i} = 600/6

F_{i} = 100 N

Hence the input force required comes out to be 100 N

ANSWERED AT 22/09/2019 - 11:53 PM


QUESTION POSTED AT 22/09/2019 - 11:53 PM

Which equations could be used as is, or rearranged to calculate for frequency of a wave? Check all that apply. 1. wavelength = frequency / speed 2. speed = frequency x wavelength 3. wavelength = speed / frequency 4. frequency = speed / wavelength 5. frequency = wavelength over speed 6. speed = wavelength x frequency

-- Equations  #2  and  #6  are both the same equation,
and are both correct.

-- If you divide each side by  'wavelength', you get Equation #4,
which is also correct.

-- If you divide each side by  'frequency', you get Equation #3,
which is also correct. 
With some work, you can rearrange this one and use it to calculate
frequency.

Summary:

-- Equations #2, #3, #4, and #6 are all correct statements,
and can be used to find frequency.

-- Equations #1 and #5 are incorrect statements.

ANSWERED AT 22/09/2019 - 11:51 PM


QUESTION POSTED AT 22/09/2019 - 11:51 PM