**Answer:**

-9. Hope this helps. Good luck on your final.

**Step-by-step explanation:**

Search

Answered @ 19/08/2019 05:51 PM By answersmine

**Answer:**

-9. Hope this helps. Good luck on your final.

**Step-by-step explanation:**

Simplify then factor

The correct answer is B.

Please provide the answer

Please provide the answer

**Answer:**

the answer on edge is

**Step-by-step explanation:**

a = 3

b= 6

**Answer:**

y = x² + 38x + 311

**Step-by-step explanation:**

If a polynomial has rational coefficients and irrational roots, then the roots must be conjugate pairs.

y = (x − (-19-5√2)) (x − (-19+5√2))

y = (x + 19+5√2) (x + 19−5√2)

Use FOIL to distribute:

y = x² + x (19−5√2) + x (19+5√2) + (19+5√2)(19−5√2)

y = x² + 19x − 5√2 x + 19x + 5√2 x + (19+5√2)(19−5√2)

y = x² + 38x + (19+5√2)(19−5√2)

Use FOIL to distribute the last term:

y = x² + 38x + 19² − 95√2 + 95√2 − 50

y = x² + 38x + 361 − 50

y = x² + 38x + 311

**Answer:**

Expanded form of the series is:

**A. -3 + 2 + 7 + 12 + 17**

**Step-by-step explanation:**

when k=1 -3+(k-1)5= -3

when k=2 -3+(k-1)5= -3+5=2

when k=3 -3+(k-1)5= -3+10=7

when k=4 -3+(k-1)5= -3+15=12

when k=5 -3+(k-1)5= -3+20=17

Hence, value of

**Hence, expanded form of the series is:**

**A. -3 + 2 + 7 + 12 + 17**

**Answer:**

**Step-by-step explanation:**

No, her answer is not correct. We square the lengths of all sides and then determine whether the Pythagorean Theorem holds here:

9² + 15² = 306. This is not equal to the square of the longest side ( that square being 395. Answer C is correct.

**Answer:**

see explanation

**Step-by-step explanation:**

Given

4x - 8x ÷ 2

Under the rules of PEMDAS , division must be performed before subtraction.

Hence

4x - 8x ÷ 2 = 4x - 4x ← dividing - 8x by 2, then

4x - 4x = 0 ← correct answer

**Question 1:**

For this case we must simplify the following expression:

We factor the numerator of the expression, looking for two numbers that when multiplied give as a result 2 and when summed give as result 3. These numbers are 2 and 1.

So:

Rewriting the expression we have:

Simplifying common terms in the numerator and denominator, we have that the expression is reduced to:

**ANswer:**

**Option A**

**Question 2:**

For this case we must find the value of the variable "x" of the following expression:

Multiplying by 12 on both sides of the equation we have:

We add 1 to both sides of the equation:

**ANswer:**

**Option A**

**Question 3:**

For this case we must find the domain of the following function:

The domain of a function is given by all the values for which the function is defined.

The given function is not defined when the denominator is 0.

Thus, the domain is given by all real numbers except 2.

**Answer:**

**OPTION C**

**Question 4:**

For this case we must simplify the following expression:

We take common factor 3 from the numerator of the expression:

We can write 6 as

Rewriting the expression we have:

Simplifying common terms of the numerator and denominator we have that the expression is reduced to:

**ANswer:**

**Option D**

**Question 5:**

For this case we must find the vertical asymptotes of the following function:

We have by definition, that the vertical asymptotes are vertical lines to which the function is approaching indefinitely without ever cutting them.

To locate the vertical asymptotes in rational functions, we find the values of "x" that annul the denominator, but not the numerator.

So:

We factor the denominator, looking for two numbers that when multiplied by -2 and when added together give 1. Thus:

Now, equaling the denominator to zero, we have that the vertical asymptote occurs in areas of infinite discontinuity of:

**Answer:**

**Option C**

**Question 6:**

For this case we must find the discontinuities and zeros of the following function:

We have by definition, that if a function is not continuous at a point, it is said that the function has a discontinuity at that point and that the function is discontinuous.

The function is undefined where the denominator equals 0.

It is a discontinuity.

Now, we factor the numerator looking for two numbers that multiplied by 6 and added by 5. These numbers are 3 and 2. Then:

Now we find the zeros of the funicon, for that we replace f (x) with y.

We eliminate common terms from the numerator and denominator.

To find the roots, we do y = 0:

**ANswer:**

**Option B**

**Question 7:**

For this case we must find the discontinuities and zeros of the following function:

We have by definition, that if a function is not continuous at a point, it is said that the function has a discontinuity at that point and that the function is discontinuous.

The function is undefined where the denominator equals 0. Then:

The function is discontinuous for and

Now factoring the denominator we have:

(x-3) (x + 3)

To find the zeros of the function we change f (x) by y.

We make y = 0:

So, the zeros of the function are at

**ANswer:**

**The function is discontinuous for and **

**The zeros of the function are at **

**Question 8:**

For this case we have:

x: Variable representing red fish

y: Variable representing blue fish

They tell us that:

Then, we substitute the second equation in the first one;

So, there are 20 blue fish.

**Answer:**

**20 blue**